Spherical Capacitor Calculator

Enter the inner radius, outer radius, dielectric constant, and voltage of two concentric conducting spheres to find the capacitance (C = 4πε₀εᵣab/(b − a)), stored charge, stored energy, and peak electric field.

Quick Facts

Capacitance formula
C = 4πε₀εᵣab / (b − a)
a = inner radius, b = outer radius (b > a), ε₀ = 8.854 × 10⁻¹² F/m.
Isolated-sphere limit
C → 4πε₀εᵣa as b → ∞
A distant outer shell behaves like a single isolated sphere.
Peak field location
E_max = Vb / [a(b − a)]
The field is strongest at the inner sphere's surface (r = a).

Your Results

Calculated
Capacitance
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C = 4πε₀εᵣab/(b − a)
Charge Stored
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Q = CV
Energy Stored
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E = ½CV²
Peak Electric Field (at r = a)
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E_max = Vb / [a(b − a)]

Ready

Enter the inner radius, outer radius, dielectric constant, and voltage, then press Calculate.

Formula and Method for the Spherical Capacitor Calculator

A spherical capacitor is two concentric conducting spheres — a solid or hollow inner sphere of radius a surrounded by a hollow outer shell of radius b (with b > a) — separated by vacuum, air, or another insulating dielectric. Applying Gauss's law to the region between the shells and integrating the electric field from a to b gives the potential difference V = Q/(4πε₀εᵣ) × (1/a − 1/b), so the capacitance C = Q/V works out to C = 4πε₀εᵣab/(b − a), where ε₀ = 8.854 × 10⁻¹² F/m is the permittivity of free space and εᵣ is the relative permittivity (dielectric constant) of the material filling the gap.

How the calculation works

Enter the inner radius a, the outer radius b, the unit they're measured in, the dielectric constant εᵣ of the material between the spheres (1 for vacuum, about 1.0006 for air), and the voltage applied between the spheres. The calculator converts both radii to meters and computes the capacitance C = 4πε₀εᵣab/(b − a). From there it finds the charge stored on each sphere (Q = CV), the energy stored in the electric field (E = ½CV²), and the peak electric field strength, which occurs at the inner sphere's surface: E_max = Q/(4πε₀εᵣa²) = Vb/[a(b − a)]. That last, voltage-only form is useful because it does not require computing Q or ε₀εᵣ separately.

Common mistakes

  • Swapping inner and outer radius: the formula requires b > a — if you enter the larger sphere as "inner," the calculator will reject it rather than silently returning a negative or nonsensical capacitance.
  • Forgetting the dielectric constant: leaving εᵣ at 1 assumes vacuum or air; a real dielectric (mica, oil, ceramic) multiplies the capacitance by its εᵣ, which is often 2–10× higher.
  • Mixing radius units: enter both radii in the same unit — the unit selector applies to both a and b, so switch it before typing new values, not after.
  • Confusing capacitance with charge: capacitance (farads) is a fixed geometric property of the two spheres; charge (coulombs) depends on the voltage you apply and changes if V changes.

Real-world applications

  • Concentric-sphere geometry is the standard idealized model used in physics courses to teach Gauss's law and capacitance because, unlike parallel plates, its field can be found exactly without edge-effect approximations.
  • Van de Graaff generators and other electrostatic high-voltage domes are approximately isolated spheres (b → ∞), so the isolated-sphere limit C = 4πε₀εᵣa is used to estimate how much charge a dome can hold before it arcs.
  • Spherical or nearly-spherical electrodes are used in high-voltage test equipment and spark-gap standards specifically because a rounded shape avoids the field concentration ("point effect") that sharp edges create.
  • Coaxial spherical shielding — a grounded outer shell around a charged inner conductor — is a simplified stand-in for spherical capacitive sensors and some particle-detector electrode geometries.

Frequently Asked Questions

What is the formula for the capacitance of a spherical capacitor?
The capacitance between two concentric conducting spheres is C = 4πε₀εᵣab/(b − a), where a is the inner sphere's radius, b is the outer sphere's radius (b > a), ε₀ = 8.854 × 10⁻¹² F/m is the permittivity of free space, and εᵣ is the relative permittivity (dielectric constant) of the material filling the gap.
What happens to the capacitance as the outer sphere gets very large?
As b approaches infinity, the ab/(b − a) term approaches a, so C approaches 4πε₀εᵣa — the classic formula for the capacitance of a single isolated conducting sphere of radius a. A spherical capacitor with a distant outer shell behaves like an isolated sphere.
Why is the electric field strongest at the inner sphere's surface?
Between the shells the field falls off as E = Q/(4πε₀εᵣr²), so it is largest at the smallest radius, r = a. This means the inner sphere's surface is the most likely place for the dielectric to break down (arc over) if the voltage is raised too high.
How does the dielectric constant (relative permittivity) change the result?
Filling the gap between the spheres with an insulating material raises the capacitance by a factor of εᵣ compared with vacuum (εᵣ = 1) or air (εᵣ ≈ 1.0006), because the dielectric partially cancels the field between the plates, letting the same charge be stored at a lower voltage.