Series Resistor Calculator

Add resistor values connected in series to get total resistance, then supply a source voltage to find circuit current, power dissipation, and the voltage drop across each resistor.

Quick Facts

Total resistance
R_total = R₁ + R₂ + R₃ + …
Resistors in series simply add — there is only one path for current.
Series current
I = V ÷ R_total
The same current flows through every resistor in the chain (Ohm's Law).
Voltage divider
Vₙ = I × Rₙ = V × (Rₙ ÷ R_total)
Each resistor's share of the source voltage is proportional to its resistance.
Power dissipated
P = I² × R_total = V × I
Total power equals the sum of I²Rₙ dissipated by each resistor as heat.

Your Results

Calculated
Total Resistance
-
R_total = R₁ + R₂ + R₃ + R₄
Circuit Current
-
I = V ÷ R_total
Total Power Dissipated
-
P = V × I
Voltage Drop per Resistor
-
Vₙ = I × Rₙ

Ready

Enter resistor values and an optional supply voltage, then press Calculate.

How to Calculate Resistors in Series

When resistors are connected end-to-end so there is only one path for current to flow, they are in series. Because charge has nowhere else to go, the same current passes through every resistor in the chain, and their resistances simply add together: R_total = R₁ + R₂ + R₃ + … + Rₙ. This calculator sums up to four resistor values and, if you provide a supply voltage, also finds the circuit current, the power dissipated, and how much voltage each resistor drops.

Why series resistances add directly

Resistance opposes current flow, and stacking resistors in series is like lengthening a single wire — each one adds its own opposition without giving current a shortcut around it. Applying Ohm's Law (V = IR) to the whole chain with a single shared current I gives V_total = I·R₁ + I·R₂ + I·R₃ + … = I·(R₁ + R₂ + R₃ + …), so the equivalent resistance seen by the source is simply the sum of the individual resistors. This is the opposite of the parallel case, where 1/R_total = 1/R₁ + 1/R₂ + …, and the combined resistance is always smaller than the smallest individual resistor.

Current, voltage divider, and power

Once R_total is known, Ohm's Law gives the single current that flows through every resistor: I = V ÷ R_total. That same current, multiplied by each resistor's value, gives its individual voltage drop: Vₙ = I × Rₙ — equivalently written as the voltage-divider rule, Vₙ = V × (Rₙ ÷ R_total). The drops across all resistors always add back up to the source voltage (Kirchhoff's Voltage Law). Power dissipated by the whole chain is P = V × I = I² × R_total, and each resistor individually dissipates I² × Rₙ as heat — check that figure against each component's power rating before building the circuit, and derate to roughly 50–70% of a resistor's rated wattage for reliable long-term operation.

Frequently Asked Questions

How do I find the total resistance of resistors in series?
Add up every resistor's value: R_total = R₁ + R₂ + R₃ + … For example, resistors of 220 Ω, 330 Ω, and 470 Ω in series give a total of 220 + 330 + 470 = 1,020 Ω.
Is the current the same through every resistor in a series circuit?
Yes. A series circuit has only one path for current, so the exact same current flows through each resistor — only the voltage dropped across each one differs, in proportion to its resistance (V = IR).
How do I calculate the voltage drop across each resistor?
Multiply the circuit current by that resistor's value: Vₙ = I × Rₙ. You can also use the voltage-divider rule directly: Vₙ = V_source × (Rₙ ÷ R_total). The individual drops always sum back up to the source voltage.
What happens if one resistor in a series string fails open?
The entire circuit breaks. Because series-connected components share a single current path, an open (infinite-resistance) failure in any one resistor stops current everywhere in that loop, so every resistor in the string reads zero current and zero voltage drop.