Car Jump Distance Calculator

Enter your launch speed, ramp angle, and the height difference to the landing surface to calculate how far a car will fly through the air using projectile motion.

Quick Facts

Range formula
D = v·cos(θ)·t
Horizontal speed stays constant in flight; only gravity changes the vertical speed.
Flight time
½gt² − v·sin(θ)·t − h = 0
Solved for t to account for a landing surface above or below the ramp.
Mass-independent
Ignoring air drag
A car's weight and horsepower do not affect distance once it leaves the ramp — only speed, angle, and height do.

Your Results

Calculated
Jump Distance
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D = v·cos(θ)·t, measured horizontally
Time of Flight
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Seconds spent airborne
Peak Height
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Highest point above the ramp
Landing Speed
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Speed when the car reaches the landing surface

Ready

Enter launch speed, ramp angle, and landing height, then press Calculate.

Formula and Method for Car Jump Distance

Once a car's wheels leave a launch ramp, it becomes a projectile: the engine can no longer push it forward, and (ignoring air resistance) gravity is the only force acting on it. Its horizontal velocity component, v·cos(θ), stays constant for the whole flight, while its vertical velocity component, v·sin(θ), is slowed, stopped, and reversed by gravity at a constant rate g = 9.80665 m/s². This calculator uses that standard projectile-motion model to find the horizontal jump distance, flight time, peak height, and landing speed from the launch speed, ramp angle, and the height difference between the ramp and the landing surface.

Deriving the flight time and distance

Measuring height y upward from the ramp, the car's vertical position at time t is y(t) = v·sin(θ)·t − ½·g·t². If the landing surface sits a height h below the ramp (h is positive for a drop, negative if the landing is higher), the car lands when y(t) = −h. Rearranging gives the quadratic ½·g·t² − v·sin(θ)·t − h = 0, which solves to t = [v·sin(θ) + √((v·sin(θ))² + 2gh)] / g. The horizontal jump distance is then simply D = v·cos(θ)·t — speed times time, since horizontal velocity never changes in flight. The same trajectory also gives the peak height above the ramp, (v·sin(θ))²/(2g), and the landing speed, found from the horizontal speed and the vertical speed at touchdown, v·sin(θ) − g·t.

How angle and height change the distance

For a landing at the same height as the ramp (h = 0), distance is maximized at a 45° launch angle — that is the classic textbook result. A landing that sits below the ramp gives the car extra time to fall before it reaches ground level, which stretches the horizontal distance and shifts the best angle to somewhat less than 45°, since a flatter, faster trajectory now covers more ground during that extra falling time. A landing above the ramp height is only reachable up to the car's peak height; beyond that height the car simply cannot get there regardless of speed or angle, and the calculator will flag the input as unreachable.

Real-world caveats

This model is idealized classical mechanics and leaves out effects that matter to an actual stunt: aerodynamic drag slows a real car in flight, energy lost to ramp friction and suspension compression at takeoff reduces the effective launch speed, and the car's rotation (nose-up or nose-down pitch) in the air changes how and where it actually touches down. Real ramp jumps are engineered with instrumented test runs, scale models, and large safety margins — treat this calculator's output as a theoretical estimate for learning and planning, never as a guarantee for an actual jump.

Frequently Asked Questions

What formula does this car jump distance calculator use?
It uses standard projectile motion. Once a car leaves the ramp, its horizontal speed stays constant at v·cos(θ) and its vertical motion is governed only by gravity. The time in the air is found by solving ½·g·t² − v·sin(θ)·t − h = 0 for t, and the horizontal jump distance is D = v·cos(θ)·t, where h is how far below the ramp the landing surface sits.
Does a heavier or more powerful car jump farther?
No — once the wheels leave the ramp, only gravity acts on the car (air resistance aside), so jump distance depends only on launch speed, ramp angle, and the height difference to landing, not on the car's mass or horsepower. A heavier and a lighter car launched at the same speed and angle travel the same distance.
What ramp angle produces the longest jump?
On a level landing (no height difference), 45° maximizes horizontal distance for a given launch speed. If the landing area is lower than the ramp, the optimal angle is somewhat less than 45°, since a flatter trajectory covers more ground before gravity pulls the car down to the lower landing height.
Why might a real car jump shorter than the calculated distance?
This calculator models ideal projectile motion and ignores aerodynamic drag, energy lost to ramp friction and suspension compression at takeoff, and the car's rotation (pitch) in the air — all of which reduce real-world distance compared with the idealized physics result. Treat the output as a theoretical estimate, not a guarantee for an actual stunt.