Brewster's Angle Calculator

Find the angle of incidence at which reflected light becomes fully polarized, from the refractive indices of the two media at the boundary.

Quick Facts

Formula
θ_B = arctan(n₂ / n₁)
n₁ is the refractive index of the medium light travels through first; n₂ is the medium beyond the interface.
Key property
Reflected light is 100% s-polarized
Named for Sir David Brewster, who described the relationship in 1815.

Your Results

Calculated
Brewster's angle
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Incidence angle for full polarization
Brewster's angle (radians)
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Same angle, radian measure
Refraction angle
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Transmitted ray angle (90° − θ_B)
Index ratio n₂ / n₁
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Equals tan(θ_B)

Ready

Enter both refractive indices, then press Calculate.

About Brewster's Angle

When unpolarized light strikes a boundary between two transparent media — air and glass, air and water, glass and plastic — most of the time both the reflected and transmitted beams come out partially polarized. But at one specific angle of incidence, something special happens: the component of light polarized parallel to the plane of incidence (p-polarized) is transmitted with zero reflection. Only the perpendicular component (s-polarized) reflects, so the reflected beam is completely, purely polarized. That special angle is called Brewster's angle, or the polarizing angle, named for Scottish physicist Sir David Brewster, who published the relationship in 1815.

The formula

Brewster's angle θ_B is found from the refractive indices of the two media:

θ_B = arctan(n₂ / n₁)

where n₁ is the refractive index of the medium the light starts in (the incident side) and n₂ is the refractive index of the medium beyond the boundary (the transmission side). For ordinary light going from air (n₁ ≈ 1.00) into window glass (n₂ ≈ 1.50), θ_B works out to about 56.3°.

Why it works

Brewster's angle has a neat geometric signature: at that angle of incidence, the reflected ray and the refracted (transmitted) ray are exactly perpendicular to each other — they sum to 90°. Combining that fact with Snell's law, n₁ sin(θ_B) = n₂ sin(θ_t), and the identity θ_t = 90° − θ_B, gives n₁ sin(θ_B) = n₂ cos(θ_B), which rearranges directly to tan(θ_B) = n₂ / n₁. Physically, the p-polarized reflection vanishes because the oscillating dipoles in the second medium that would radiate the reflected wave are aligned along the direction the reflected ray would have to travel — a dipole cannot radiate along its own axis, so no p-polarized light is reflected in that direction.

Knowing the limits

The formula above assumes both media are transparent, non-absorbing dielectrics (like glass, water, or air) and that the incident light is a simple plane wave hitting a flat, smooth interface. It does not directly apply to metals or other conductive/absorbing materials, where the refractive index is complex and the "Brewster angle" (if it exists at all) behaves differently. It also does not account for multiple layers or coatings, which need the full Fresnel equations layer by layer. Refractive index itself varies slightly with the wavelength of light (dispersion), so for precise work use the index value that matches your light source.

Frequently Asked Questions

What is Brewster's angle?
Brewster's angle (the polarizing angle) is the angle of incidence at which light hitting a transparent boundary reflects with no p-polarized component. Only s-polarized light reflects at that angle, so the reflected beam is completely linearly polarized. It is found from θ_B = arctan(n₂ / n₁), using the refractive indices of the two media.
Why does θ_B + θ_t equal 90 degrees?
At Brewster's angle, the reflected ray and the refracted (transmitted) ray are perpendicular to each other. Combined with Snell's law, n₁ sin(θ_B) = n₂ sin(θ_t), that geometric fact leads directly to tan(θ_B) = n₂ / n₁ — the Brewster's angle formula. So once θ_B is known, the refraction angle is always 90° − θ_B.
Is Brewster's angle the same as the critical angle?
No. The critical angle governs total internal reflection and only exists when light travels from a denser medium into a less dense one (n₁ > n₂); beyond it, no light is transmitted. Brewster's angle exists for any pair of transparent media and is about polarization, not total reflection — the s-polarized component still reflects at Brewster's angle, just not the p-polarized one.
Does Brewster's angle depend on the color of the light?
Indirectly, yes. The formula only uses n₁ and n₂, but refractive index changes slightly with wavelength (dispersion), so Brewster's angle for red light through a given piece of glass differs slightly from that for blue light. Use the refractive index for the wavelength you care about for the most accurate result.