AC Wattage Calculator

Calculate real power (watts), apparent power (VA), and reactive power (VAR) for an AC circuit from voltage, current, and power factor.

Quick Facts

Formula
P = V x I x PF (single-phase); P = sqrt(3) x V x I x PF (three-phase)
Real power (W) is apparent power (VA) scaled by the power factor.
Power factor
Ranges from 0 to 1
1.0 means voltage and current are perfectly in phase (purely resistive load).

Your Results

Calculated
Real power
-
Actual work performed (watts)
Apparent power
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Voltage x current (VA)
Reactive power
-
Non-working power (VAR)
Real power (kW)
-
Same value in kilowatts

Ready

Enter voltage, current, and power factor, then press Calculate.

Understanding AC wattage

On an AC circuit, "watts" and "volt-amps" are not always the same thing. This calculator converts voltage, current, and power factor into the three quantities that describe AC power: real power (the energy that actually does work, in watts), apparent power (what you get from simply multiplying voltage by current, in volt-amps), and reactive power (the non-working portion that oscillates in and out of magnetic or electric fields, in VAR).

The formulas

  • Apparent power: S = V × I for a single-phase circuit, or S = √3 × V × I for a balanced three-phase circuit using line-to-line voltage and line current.
  • Real power: P = S × PF, where PF is the power factor — a unitless number between 0 and 1 describing how in-phase the voltage and current are.
  • Reactive power: Q = √(S² − P²), the component of apparent power that does not convert to real work.

Why power factor matters

For a purely resistive load (a heater, incandescent bulb, or toaster), current and voltage rise and fall together, PF = 1, and watts equal volt-amps exactly. Motors, transformers, and many electronic power supplies present an inductive or capacitive load, so current lags or leads voltage. That phase shift means some of the apparent power sloshes back and forth without doing useful work — the power factor is the fraction that remains real, useful power. A lower power factor means more current is required to deliver the same wattage, which is why utilities sometimes charge industrial customers extra for poor power factor.

Single-phase vs. three-phase

Household and small-appliance circuits are almost always single-phase, so apparent power is simply voltage times current. Three-phase power, common in commercial and industrial equipment, splits the load across three conductors 120° apart; for a balanced three-phase load the total power is √3 (about 1.732) times the single-phase calculation using the line-to-line voltage and line current.

Frequently Asked Questions

What is the formula for AC wattage?
Real power in watts equals P = V x I x PF for a single-phase circuit, where V is voltage, I is current in amps, and PF is the power factor (a number from 0 to 1). For a balanced three-phase circuit using line-to-line voltage and line current, the formula is P = square root of 3 x V x I x PF.
Why isn't wattage just volts times amps?
Volts times amps gives apparent power in volt-amps (VA), not real power in watts. On AC circuits with inductive or capacitive loads (motors, transformers, some electronics), voltage and current fall out of phase, so only a fraction of the apparent power does real work. The power factor is that fraction; for purely resistive loads like heaters and incandescent bulbs, PF is 1 and watts equal volt-amps.
What is a good power factor?
A power factor of 0.95 to 1.0 is considered excellent and typical of resistive loads. Motors, HVAC compressors, and fluorescent or LED drivers without correction often run 0.7 to 0.9. Utilities may charge commercial customers a penalty when the power factor drops much below 0.85, since more current is needed to deliver the same real power.
What is reactive power?
Reactive power (measured in VAR, volt-amps reactive) is the portion of apparent power that shuttles back and forth to build and collapse magnetic or electric fields in inductive or capacitive loads without doing useful work. It relates to real and apparent power by S squared = P squared + Q squared, so Q = square root of (S squared - P squared).