Chebyshev's Theorem Calculator

Find the minimum fraction of any dataset that lies within k standard deviations of the mean, using Chebyshev's bound 1 − 1/k². Works for every distribution shape.

Quick Facts

Formula
At least 1 − 1/k² of values fall within k standard deviations of the mean
Distribution-free: holds for any data set when k > 1. At k=2, at least 75%; at k=3, at least 88.89%.

Your Results

Calculated
Minimum fraction within k SDs
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Chebyshev bound 1 − 1/k²
Maximum fraction outside k SDs
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At most 1/k²
Interval (mean ± k·SD)
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Range that holds the minimum fraction

Ready

Enter k (greater than 1) and press Calculate.

Using Chebyshev's Theorem

Chebyshev's theorem (also called Chebyshev's inequality) gives a guaranteed lower bound on how much of a data set clusters near its mean, without assuming anything about the shape of the distribution. For any data set — skewed, bimodal, spiky, or bell-shaped — at least 1 − 1/k² of the observations lie within k standard deviations of the mean, for any k > 1. Enter k above to get that minimum fraction; add a mean and standard deviation to see the actual interval it covers.

The formula

If a data set has mean μ and standard deviation σ, then for any k > 1:

Proportion within [μ − kσ, μ + kσ] ≥ 1 − 1/k²

Equivalently, at most 1/k² of the values fall more than k standard deviations from the mean. The bound is a floor, not an exact percentage: a specific data set usually has more than 1 − 1/k² of its values inside the interval, but never fewer.

Why it is useful

The familiar empirical rule (68% within 1σ, 95% within 2σ, 99.7% within 3σ) only applies to roughly normal distributions. When you cannot assume normality — income data, insurance claims, reliability lifetimes, exam scores with a heavy tail — Chebyshev still holds. It lets you make a rigorous "at least this much" statement about outliers using nothing but the mean and standard deviation, which is why it appears in the proofs behind the weak law of large numbers.

Common reference values

  • k = 1.5: at least 1 − 1/2.25 = 55.56% of values within 1.5 SDs.
  • k = 2: at least 1 − 1/4 = 75% within 2 SDs (at most 25% outside).
  • k = 2.5: at least 1 − 1/6.25 = 84% within 2.5 SDs.
  • k = 3: at least 1 − 1/9 = 88.89% within 3 SDs (at most 11.11% outside).
  • k = 4: at least 1 − 1/16 = 93.75% within 4 SDs.

Frequently Asked Questions

What does Chebyshev's Theorem say?
For any data set or probability distribution, at least 1 − 1/k² of the values lie within k standard deviations of the mean, for any k greater than 1. It makes no assumption about the shape of the distribution, so the result is a guaranteed minimum rather than an exact percentage.
Why must k be greater than 1?
At k = 1 the bound 1 − 1/k² equals 0, and for k below 1 it is negative, so the theorem tells you nothing there. It only produces a positive, useful minimum once k exceeds 1. For example k = 2 gives at least 75% and k = 3 gives at least 88.89%.
How is this different from the empirical (68-95-99.7) rule?
The empirical rule gives exact percentages but only for approximately normal, bell-shaped data. Chebyshev gives a weaker bound (75% instead of 95% at 2σ) but is valid for every distribution. Use the empirical rule when normality is reasonable; fall back to Chebyshev when it is not.
Can the actual proportion be higher than the bound?
Yes. Chebyshev is a worst-case guarantee. Most real data sets have far more than 1 − 1/k² of their values within k SDs — a normal distribution has about 95% within 2σ versus Chebyshev's guaranteed 75%. The bound is tight only for specially constructed distributions.