6 Sided Dice Probability Calculator

Find the exact odds of rolling a target sum with one or more standard six-sided dice — the number of ways, the probability as a fraction, decimal and percent, plus the cumulative "at least" and "at most" odds.

Quick Facts

Method
Exact count of favorable outcomes ÷ 6N total outcomes
Every ordered roll is equally likely, so probability = ways to make the sum divided by 6 to the power of the number of dice.

Your Results

Calculated
P(sum = target)
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Probability of exactly this sum
Ways / Total
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Favorable outcomes out of 6ᴺ
P(sum ≥ target)
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Chance of this sum or higher
P(sum ≤ target)
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Chance of this sum or lower

Ready

Enter the number of dice and a target sum, then press Calculate.

How 6-sided dice probability works

A standard six-sided die (a d6) is a fair cube with faces numbered 1 through 6. On a single roll, each face is equally likely, so the probability of any one specific number is 1/6 ≈ 16.67%. Dice problems get interesting when you roll several dice and ask about the sum of the faces. This calculator answers exactly that: given N dice and a target total, it counts how many of the possible rolls hit that total and divides by the number of rolls that can occur.

The core formula

Every ordered outcome of N dice is equally likely, and there are 6N of them (6 faces on the first die × 6 on the second × … × 6 on the Nth). So:

P(sum = t) = (number of ordered rolls that total t) ÷ 6N

For a single die the answer is trivial — one way each for the totals 1 through 6, so 1/6 apiece. For two dice there are 62 = 36 ordered outcomes. The calculator finds the numerator by building the full distribution of sums with a repeated convolution: start with one die, then combine it with the next die face by face until all N dice are accounted for. That gives an exact integer count for every reachable sum, so the probabilities are exact fractions, not simulations or estimates.

Why the middle sums are most likely

With two dice the possible totals run from 2 (rolling 1 and 1) to 12 (rolling 6 and 6). There is only one way to make 2 and only one way to make 12, but six different ways to make 7 — (1,6), (2,5), (3,4), (4,3), (5,2), (6,1). That is why 7 is the most common roll in games like craps: P(7) = 6/36 = 1/6 ≈ 16.67%. As you add more dice, the distribution of sums bunches even more tightly around the middle and takes on the familiar bell shape (a consequence of the Central Limit Theorem).

Two-dice reference table

These are the exact probabilities for the sum of two standard dice — the single most common dice-probability question:

SumWaysProbabilityPercent
211/362.78%
321/185.56%
431/128.33%
541/911.11%
655/3613.89%
761/616.67%
855/3613.89%
941/911.11%
1031/128.33%
1121/185.56%
1211/362.78%

The 11 possible sums add up to 36/36 = 1, and the table is symmetric around 7 — a sum of 6 is exactly as likely as a sum of 8, and 2 is as likely as 12.

Frequently Asked Questions

What is the probability of rolling a 7 with two dice?
A sum of 7 is the most likely outcome with two six-sided dice. There are 6 ordered ways to make it — (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — out of 36 equally likely outcomes, so P(7) = 6/36 = 1/6 ≈ 16.67%.
What are the odds of rolling doubles?
"Doubles" means both dice show the same number. There are 6 such outcomes — (1,1) through (6,6) — out of 36, so the probability of rolling any doubles is 6/36 = 1/6 ≈ 16.67%. The chance of a specific double, such as double sixes, is 1/36 ≈ 2.78%.
Does this calculator work for more than two dice?
Yes. Enter any number of dice from 1 to 20. For three dice the totals range from 3 to 18 across 216 outcomes; for example a sum of 10 or 11 is most likely at 27/216 = 1/8 = 12.5% each. The tool computes the exact distribution for whatever N you choose.
What is the difference between "exactly", "at least", and "at most"?
P(sum = target) is the chance of hitting that total exactly. P(sum ≥ target) adds up every outcome at or above the target, and P(sum ≤ target) adds up every outcome at or below it. The at-least and at-most figures for the same target always overlap at the exact sum, so they add up to 1 plus P(sum = target).