Elongation Calculator

Find how far a rod, wire, or bar stretches under a tensile axial load using δ = F·L₀ / (A·E), the elastic deformation formula from Hooke's Law, plus the resulting stress, strain, and final length.

Quick Facts

Elongation formula
δ = F·L₀ / (A·E)
Axial deformation under tensile load, from Hooke's Law.
Stress-strain law
σ = E·ε
Holds only within the material's elastic (linear) range.
Typical E values
Steel ≈ 200 GPa, Aluminum ≈ 69 GPa
Young's modulus depends on material, not geometry.

Your Results

Calculated
Elongation (δ)
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δ = F × L₀ / (A × E), in mm
Axial Stress (σ)
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σ = F / A, in MPa
Strain (ε)
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ε = δ / L₀ = σ / E
Final Length (L₀ + δ)
-
Stretched length under load

Ready

Enter the load, geometry, and material, then press Calculate.

Formula and Method for the Elongation Calculator

When a rod, wire, or bar is pulled by an axial tensile force, it stretches by a small amount called elongation (δ). For loads that stay within the material's elastic range, this stretch follows directly from Hooke's Law extended to solids: δ = F·L₀ / (A·E), where F is the applied axial force, L₀ is the original length, A is the cross-sectional area, and E is the material's Young's modulus (a measure of stiffness). This calculator also derives the axial stress, strain, and final stretched length from the same inputs.

How the calculation works

Enter the axial force, the original length (with its unit), the cross-sectional area, and either pick a material or enter a custom Young's modulus. The calculator first finds the axial stress, σ = F / A (in MPa, since 1 MPa = 1 N/mm²). Dividing stress by the modulus gives the strain, ε = σ / E — the fractional change in length. Multiplying strain by the original length gives the elongation, δ = ε × L₀, which is algebraically the same as δ = F·L₀ / (A·E). Adding δ to the original length gives the final, stretched length.

Common mistakes

  • Mixing units: keep force in newtons, area in mm², and modulus in GPa (or convert everything to consistent SI units first) — mismatched units are the most common source of wrong answers.
  • Exceeding the elastic limit: δ = FL₀/(AE) only holds while stress stays below the material's yield strength; beyond that point the deformation becomes permanent (plastic) and the formula no longer applies.
  • Confusing elongation with strain: elongation (δ) is an absolute length change (e.g., in mm); strain (ε) is that change divided by the original length — a dimensionless ratio, often shown as a percentage.

Real-world applications

  • Structural and mechanical engineers use this formula to check how much a bolt, cable, or column stretches under a known load, and to size members so stress stays within a safe margin.
  • Wire rope and crane-cable specifications use axial deformation limits to avoid excessive sag or fatigue.
  • Tensile testing uses the same stress-strain relationship in reverse — measuring δ under a known F to back out a sample's Young's modulus.
  • Manufacturing tolerances account for elastic stretch in tensioned belts, filaments, fasteners, and cables.

Frequently Asked Questions

What is the formula for elongation under axial load?
Elongation under an axial tensile load is δ = F·L₀ / (A·E), where F is the applied force, L₀ is the original length, A is the cross-sectional area, and E is the material's Young's modulus. For example, a 2 m steel rod (E ≈ 200 GPa) with a 100 mm² cross-section under a 5,000 N load stretches about 0.5 mm.
What is the difference between elongation and strain?
Elongation (δ) is the absolute change in length, usually reported in millimeters or inches. Strain (ε) is elongation divided by the original length, ε = δ / L₀ — a dimensionless ratio, often expressed as a percentage, that lets you compare deformation across parts of different sizes.
Does this formula apply to compression as well as tension?
The same relationship, δ = FL₀/(AE), describes axial shortening under a compressive load, but only for members short and stocky enough that buckling isn't a concern. For slender columns under compression, buckling — not simple axial deformation — usually governs, and a separate stability check (such as Euler's formula) is needed.
What happens if the load exceeds the elastic limit?
This formula assumes linear-elastic behavior, where stress is proportional to strain (Hooke's Law). If the applied stress exceeds the material's yield strength, part of the deformation becomes permanent (plastic) and the actual elongation will be larger than δ = FL₀/(AE) predicts. Check the material's yield strength before relying on this formula near its limits.