How to Solve Similar Triangles
Two triangles are similar when their corresponding angles are equal and their corresponding sides are proportional. That single proportion is called the scale factor, k. If Triangle 1 has sides a, b, c and Triangle 2 has the corresponding sides a′, b′, c′, then a′/a = b′/b = c′/c = k. Once you know any one pair of corresponding sides, you can find the scale factor and use it to solve for every other side of the second triangle.
The proportionality method, step by step
Given a fully known Triangle 1 (sides a, b, c) and a single known side of Triangle 2 that corresponds to side a, the calculator finds the scale factor first: k = a′ / a. It then applies that same factor to the other two sides: b′ = b × k and c′ = c × k. Because perimeter is a linear sum of the sides, the perimeter also scales by k (Perimeter2 = Perimeter1 × k), while area scales by k² (Area2 = Area1 × k²) since area depends on two linear dimensions multiplied together.
Checking your triangle is valid
- Triangle inequality: any three side lengths only form a real triangle if the sum of the two shorter sides exceeds the longest side (a + b > c, a + c > b, b + c > a). The calculator checks this for Triangle 1 before solving.
- Similarity criteria (AA, SAS, SSS): in practice you confirm two triangles are similar via Angle-Angle (two equal angle pairs), Side-Angle-Side (two proportional sides with the included angle equal), or Side-Side-Side (all three sides proportional). This calculator assumes similarity is already established and focuses purely on solving the proportion.
- Scale factor direction: k > 1 means Triangle 2 is larger than Triangle 1; 0 < k < 1 means it is smaller. A scale factor of exactly 1 means the triangles are congruent, not just similar.
Common uses
Similar triangles show up in map and blueprint scaling, indirect height measurement (using shadows or a mirror), photography and projection scaling, engineering scale models, and countless geometry proofs. Whenever one triangle is a scaled copy of another, this same a′/a = b′/b = c′/c relationship lets you solve for any missing length.